In my previous post I talked about the importance of encryption in the database. To be fair, sometimes it really isn't important, its just required for some reason. This is more of a solution to the 2nd, as part of an overall security scheme. Also, for a scenario where some of the data in a table is replicated to other databases/platforms, etc, this could be a way to auto-obfuscate. The encrypted data would be moved through GG or w/e CDC you use without a key...making it very secure after it leaves the database.
We're going to use a block cipher...so first, you need to pick a cipher algorithm (here are the block options), a block cipher chaining modifier and a padding modifier from below, and add up their associated numbers. (ie: AES256 with CBC and PKCS5 would be 8+256+4096=4360) We'll use 4360 for our example.
Here are some of the options in dbms_crypto:
-- Block Cipher Algorithms
ENCRYPT_DES := 1;
ENCRYPT_3DES_2KEY := 2;
ENCRYPT_3DES := 3;
ENCRYPT_AES := 4;
ENCRYPT_PBE_MD5DES := 5;
ENCRYPT_AES128 := 6;
ENCRYPT_AES192 := 7;
ENCRYPT_AES256 := 8;
-- Block Cipher Chaining Modifiers
CHAIN_CBC := 256;
CHAIN_CFB := 512;
CHAIN_ECB := 768;
CHAIN_OFB := 1024;
-- Block Cipher Padding Modifiers
PAD_PKCS5 := 4096;
PAD_NONE := 8192;
PAD_ZERO := 12288;
PAD_ORCL := 16384;
1. First, create a key and capture the string that gets generated...don't lose this key:
set serveroutput on size 1000000
declare
v_Number number := 256/8; --256 bit key
v_Key RAW(32);
begin
v_Key := DBMS_CRYPTO.RANDOMBYTES(v_Number);
dbms_output.put_line(v_Key);
end;
2. Now replace the red string below with the output generated above. This is meant as a very simple example. In real life you'd want to do everything you can to make this complex and difficult to read. Putting it in a package and wrapping it would make it slightly less simple to get at. Putting this data somewhere else encypted (like the OS or a different db) would be better. How you do this is up to you...but just creating a plain text function isn't sufficient, and depending on plsql wrap is a bad idea...as Tom Kyte put it, "Using the latest wrap would provide the highest degree of "protection". That is all. I put "protection" in quotes because I've always been amused by 'wrapping' code." I'll explain that more in a different post.
We're going to use a block cipher...so first, you need to pick a cipher algorithm (here are the block options), a block cipher chaining modifier and a padding modifier from below, and add up their associated numbers. (ie: AES256 with CBC and PKCS5 would be 8+256+4096=4360) We'll use 4360 for our example.
Here are some of the options in dbms_crypto:
-- Block Cipher Algorithms
ENCRYPT_DES := 1;
ENCRYPT_3DES_2KEY := 2;
ENCRYPT_3DES := 3;
ENCRYPT_AES := 4;
ENCRYPT_PBE_MD5DES := 5;
ENCRYPT_AES128 := 6;
ENCRYPT_AES192 := 7;
ENCRYPT_AES256 := 8;
-- Block Cipher Chaining Modifiers
CHAIN_CBC := 256;
CHAIN_CFB := 512;
CHAIN_ECB := 768;
CHAIN_OFB := 1024;
-- Block Cipher Padding Modifiers
PAD_PKCS5 := 4096;
PAD_NONE := 8192;
PAD_ZERO := 12288;
PAD_ORCL := 16384;
1. First, create a key and capture the string that gets generated...don't lose this key:
set serveroutput on size 1000000
declare
v_Number number := 256/8; --256 bit key
v_Key RAW(32);
begin
v_Key := DBMS_CRYPTO.RANDOMBYTES(v_Number);
dbms_output.put_line(v_Key);
end;
2. Now replace the red string below with the output generated above. This is meant as a very simple example. In real life you'd want to do everything you can to make this complex and difficult to read. Putting it in a package and wrapping it would make it slightly less simple to get at. Putting this data somewhere else encypted (like the OS or a different db) would be better. How you do this is up to you...but just creating a plain text function isn't sufficient, and depending on plsql wrap is a bad idea...as Tom Kyte put it, "Using the latest wrap would provide the highest degree of "protection". That is all. I put "protection" in quotes because I've always been amused by 'wrapping' code." I'll explain that more in a different post.
create or replace function blackan.my_key return varchar2 as
begin
return '0F9157255C4CB6292D5C7E5FE96D90B2B4DE33CF4FEF2742366705F36D40A143';
end;
3. Now generate the base table and the decrypting view on the table:
drop table blackan.hacker_booty_base;
create table blackan.hacker_booty_base (EmpName raw(120), Emp_Num raw(88), SSN raw(80), Credit_Card raw(120), CC_Ex_Date raw(88), Address raw(120), PW raw(120));
create or replace view blackan.hacker_booty as
select
SUBSTRB(UTL_I18N.RAW_TO_CHAR (DBMS_CRYPTO.DECRYPT(EmpName,4360,my_key), 'AL32UTF8'),1,30) EmpName,
SUBSTRB(UTL_I18N.RAW_TO_CHAR (DBMS_CRYPTO.DECRYPT(Emp_Num,4360,my_key), 'AL32UTF8'),1,22) Emp_Num,
SUBSTRB(UTL_I18N.RAW_TO_CHAR (DBMS_CRYPTO.DECRYPT(SSN,4360,my_key), 'AL32UTF8'),1,20) SSN,
SUBSTRB(UTL_I18N.RAW_TO_CHAR (DBMS_CRYPTO.DECRYPT(Credit_Card,4360,my_key), 'AL32UTF8'),1,30) Credit_Card,
SUBSTRB(UTL_I18N.RAW_TO_CHAR (DBMS_CRYPTO.DECRYPT(CC_Ex_Date,4360,my_key), 'AL32UTF8'),1,30) CC_Ex_Date,
SUBSTRB(UTL_I18N.RAW_TO_CHAR (DBMS_CRYPTO.DECRYPT(Address,4360,my_key), 'AL32UTF8'),1,30) Address,
SUBSTRB(UTL_I18N.RAW_TO_CHAR (DBMS_CRYPTO.DECRYPT(PW,4360,my_key), 'AL32UTF8'),1,30) PW
from hacker_booty_base;
4. Now create the encrypting "instead of" trigger on the view to redirect the dml to the base table after encrypting it:
CREATE OR REPLACE TRIGGER blackan.ioiudr_hacker_booty
INSTEAD OF INSERT OR UPDATE OR DELETE
ON blackan.hacker_booty
FOR EACH ROW
BEGIN
if INSERTING then
insert into hacker_booty_base values (
DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW(:NEW.EmpName,'AL32UTF8'),4360,my_key),
DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.Emp_Num, 'AL32UTF8'),4360,my_key),
DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.SSN, 'AL32UTF8'),4360,my_key),
DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.Credit_Card, 'AL32UTF8'),4360,my_key),
DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.CC_Ex_Date, 'AL32UTF8'),4360,my_key),
DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.Address, 'AL32UTF8'),4360,my_key),
DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.PW, 'AL32UTF8'),4360,my_key));
elsif updating then
update hacker_booty_base set
EmpName=DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW(:NEW.EmpName,'AL32UTF8'),4360,my_key),
Emp_Num=DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.Emp_Num, 'AL32UTF8'),4360,my_key),
SSN=DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.SSN, 'AL32UTF8'),4360,my_key),
Credit_Card=DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.Credit_Card, 'AL32UTF8'),4360,my_key),
CC_Ex_Date=DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.CC_Ex_Date, 'AL32UTF8'),4360,my_key),
Address=DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.Address, 'AL32UTF8'),4360,my_key),
PW=DBMS_CRYPTO.ENCRYPT(UTL_I18N.STRING_TO_RAW (:NEW.PW, 'AL32UTF8'),4360,my_key)
where SSN=:OLD.SSN;
else
delete from hacker_booty_base where SSN=:OLD.SSN;
end if;
end;
...and that's it. Let's insert a row of fake data:
insert into blackan.hacker_booty values ('Richy Rich',1,'123-45-6789','111 2222 3333 4444', sysdate+365, '1 Main St, St Louis, MO, 12345', 'Shhh');
When you look at the actual data-at-rest, its encrypted:
select empname, emp_num, ssn from blackan.hacker_booty_base;
EMPNAME | EMP_NUM | SSN |
454460100E82C91F8B26AEE3E35EE3E8 | 9F1BE1034151056A760A880E5D7BC5C3 | 29B471D31D8E2255D1B0C7B6D5084759 |
When you look at the data via your application, which would use the view, you see the data exactly as you entered it:
select empname, emp_num, ssn from blackan.hacker_booty;
EMPNAME,EMP_NUM,SSN
Richy Rich 1 123-45-6789
No comments:
Post a Comment